Lemyte

GATE 2020 EE question paper PDF and answer key

The official GATE 2020 Electrical Engineering paper, organised by IIT Delhi: 65 questions for 100 marks in 3 hours. Download the official question paper and answer key as PDFs. Below is how the marks were split by topic, the complete official answer key and 5 questions solved step by step.

Take this paper as a timed testTry the free demo
Question paper (PDF)Official answer key (PDF)

Source: the official paper and answer key published by IIT Delhi for GATE 2020 (official GATE site). Spotted a mistake? Email team@lemyte.com.

General Aptitude
10 · 15 marks
Electrical Engineering
55 · 85 marks
MCQ / MSQ / NAT
43 / 0 / 22
Marks to all
Q 22, 52, 58, 63

Where the marks were

GATE 2020 EE topic-wise marks

Electrical Engineering questions only; General Aptitude adds 15 marks on top. The top three topics carried 31 of the 85 subject marks.

TopicQuestionsMarks
Electrical Machines711
Control Systems711
Signals and Systems69
Power Systems69
Analog and Digital Electronics69
Power Electronics68
Electromagnetic Fields48
Calculus46
Electric Circuits46
Electrical and Electronic Measurements24
Linear Algebra12
Complex Variables11
Differential Equations11

Free solved questions

5 solved questions from GATE 2020 EE

Question text and figures as in the official paper, the answer from the official key, and a worked solution. The other 60 solutions are in your report after you take the paper.

Q8 · General Aptitude · MCQ · 2 marks

In four-digit integer numbers from 1001 to 9999, the digit group “37” (in the same sequence) appears _____ times.

  • (A)
    270
  • (B)
    279
  • (C)
    280
  • (D)
    299

Answer (official key): C

Solution

Count occurrences by position:

  • 37xx: 100 numbers.
  • x37x: 9×10=909 \times 10 = 90.
  • xx37: 9×10=909 \times 10 = 90 (first two digits 10–99).

Total =280= 280 occurrences. (The number 3737 contains the group twice, so it is counted twice.)

Q10 · General Aptitude · MCQ · 2 marks

The revenue and expenditure of four different companies P, Q, R and S in 2015 are shown in the figure. If the revenue of company Q in 2015 was 20% more than that in 2014, and company Q had earned a profit of 10% on expenditure in 2014, then its expenditure (in million rupees) in 2014 was _____.

Figure for GATE 2020 EE question 10 (Analytical Aptitude)

  • (A)
    32.7
  • (B)
    33.7
  • (C)
    34.1
  • (D)
    35.1

Answer (official key): C

Solution

Q's revenue in 2015 is 45, so in 2014 it was 451.2=37.5\frac{45}{1.2} = 37.5. A 10% profit on expenditure means revenue =1.1×= 1.1 \times expenditure, so expenditure =37.51.1=34.1= \frac{37.5}{1.1} = 34.1 million rupees.

Q29 · Electric Circuits · Numerical · 1 mark

The Thevenin equivalent voltage, VTHV_{TH}, in V (rounded off to 2 decimal places) of the network shown below, is __________

Figure for GATE 2020 EE question 29 (Electric Circuits)

Answer (official key): 13.8 to 14.2

Solution

The 3 Ω across the 4 V source doesn't affect the rest. With the output open, the 5 A source flows back through the 2 Ω into the source side. So the middle node is 4+5×2=144 + 5 \times 2 = 14 V, and no current flows in the output 3 Ω: VTH=14.00V_{TH} = 14.00 V.

Q30 · Power Electronics · Numerical · 1 mark

A double pulse measurement for an inductively loaded circuit controlled by the IGBT switch is carried out to evaluate the reverse recovery characteristics of the diode, D, represented approximately as a piecewise linear plot of current vs time at diode turn-off. LparL_{par} is a parasitic inductance due to the wiring of the circuit, and is in series with the diode. The point on the plot (indicate your choice by entering 1, 2, 3 or 4) at which the IGBT experiences the highest current stress is ________.

Figure for GATE 2020 EE question 30 (Power Electronics)

Answer (official key): 3

Solution

When the IGBT turns on, it carries the load current plus the diode's reverse-recovery current. That sum is largest at the peak reverse diode current, point 3.

Q31 · Electrical Machines · Numerical · 1 mark

A single-phase, 4 kVA, 200 V/100 V, 50 Hz transformer with laminated CRGO steel core has rated no-load loss of 450 W. When the high-voltage winding is excited with 160 V, 40 Hz sinusoidal ac supply, the no-load losses are found to be 320 W. When the high-voltage winding of the same transformer is supplied from a 100 V, 25 Hz sinusoidal ac source, the no-load losses will be ______________ W (rounded off to 2 decimal places).

Answer (official key): 162.41 to 162.59

Solution

V/f=4V/f = 4 in all three cases, so BmB_m is constant and P=Af+Bf2P = Af + Bf^2:

  • 450=50A+2500B450 = 50A + 2500B
  • 320=40A+1600B320 = 40A + 1600B

This gives B=0.1B = 0.1 and A=4A = 4. At 25 Hz: 100+62.5=162.50100 + 62.5 = 162.50 W.

The other 60 questions are solved in your report when you take GATE 2020 EE as a 3-hour test.

Take GATE 2020 EE as a test

Official answer key

GATE 2020 EE answer key

All 65 answers from the official key. Numerical answers are ranges; “or” means the key accepts either answer.

Download the official GATE 2020 EE answer key (PDF)
QTopicTypeMarksAnswer
1Verbal AptitudeMCQ1C
2Verbal AptitudeMCQ1B
3Verbal AptitudeMCQ1C
4Verbal AptitudeMCQ1B
5Quantitative AptitudeMCQ1C
6Analytical AptitudeMCQ2B
7Analytical AptitudeMCQ2C
8Quantitative AptitudeMCQ2C
9Quantitative AptitudeMCQ2A
10Analytical AptitudeMCQ2C
11CalculusMCQ1A or A, D
12CalculusMCQ1C
13Signals and SystemsMCQ1B
14Signals and SystemsMCQ1D
15Complex VariablesMCQ1C
16Signals and SystemsMCQ1A
17Electrical MachinesMCQ1A
18Power SystemsMCQ1D
19Power SystemsMCQ1A
20Control SystemsMCQ1A
21Power ElectronicsMCQ1C
22Power ElectronicsMCQ1Marks to all
23Control SystemsMCQ1C
24Analog and Digital ElectronicsMCQ1A
25Analog and Digital ElectronicsMCQ1B
26Differential EquationsNumerical10.8774 to 0.8952
27Electrical MachinesNumerical14.1 to 4.4
28Electric CircuitsNumerical11.7 to 1.75
29Electric CircuitsNumerical113.8 to 14.2
30Power ElectronicsNumerical13
31Electrical MachinesNumerical1162.41 to 162.59
32Power ElectronicsNumerical119.9 to 20.2
33Power SystemsNumerical1123 to 135
34Control SystemsNumerical12
35Analog and Digital ElectronicsNumerical10
36CalculusMCQ2A
37Electromagnetic FieldsMCQ2C
38Electrical MachinesMCQ2C
39Power SystemsMCQ2C
40Analog and Digital ElectronicsMCQ2D
41Analog and Digital ElectronicsMCQ2B
42Electric CircuitsMCQ2C
43Electromagnetic FieldsMCQ2D
44Control SystemsMCQ2B
45Control SystemsMCQ2C
46Control SystemsMCQ2B
47Signals and SystemsMCQ2C
48Signals and SystemsMCQ2B
49Signals and SystemsMCQ2C
50Electromagnetic FieldsMCQ2D
51Control SystemsMCQ2A
52Linear AlgebraMCQ2Marks to all
53Electrical MachinesMCQ2A
54CalculusNumerical2-3.05 to -2.95
55Electric CircuitsNumerical254 to 56
56Electrical MachinesNumerical2123 to 127
57Power SystemsNumerical21.11 to 1.13
58Electrical MachinesNumerical2Marks to all
59Power SystemsNumerical21.01 to 1.03
60Power ElectronicsNumerical24.95 to 5.05
61Power ElectronicsNumerical24.51 to 5.1
62Electrical and Electronic MeasurementsNumerical211.5 to 12
63Electrical and Electronic MeasurementsNumerical2Marks to all
64Analog and Digital ElectronicsNumerical2210
65Electromagnetic FieldsNumerical2138.1 to 139.2

Questions about GATE 2020 EE

How many questions are in the GATE 2020 EE paper?

65 questions for 100 marks: 10 General Aptitude questions worth 15 marks and 55 Electrical Engineering questions worth 85 marks. By type, there were 43 MCQs, 22 numerical answer (NAT) questions. The paper lasted 3 hours.

Is there negative marking in GATE 2020 EE?

Yes, for MCQs only. A wrong MCQ answer costs one-third of its marks (−⅓ for a 1-mark question, −⅔ for a 2-mark question). MSQ and numerical (NAT) questions have no negative marking, and an MSQ earns marks only when every correct option is chosen.

Which topics carried the most marks in GATE 2020 EE?

Outside General Aptitude, the biggest topics were Electrical Machines (11 marks), Control Systems (11 marks), Signals and Systems (9 marks). The full topic-wise split is in the table on this page.

Were any GATE 2020 EE questions awarded marks to all?

Yes. The official key awarded full marks to everyone for questions 22, 52, 58, 63.

Where does this GATE 2020 EE answer key come from?

From the official answer key published by IIT Delhi, which organised GATE 2020. Range answers for numerical questions and questions with more than one accepted answer are kept exactly as the key gives them.

More GATE papers