GATE 2025 EC question paper PDF and answer key

The official GATE 2025 Electronics & Communication Engineering paper, organised by IIT Roorkee: 65 questions for 100 marks in 3 hours. Download the official question paper and answer key as PDFs. Below is how the marks were split by topic, the complete official answer key and 5 questions solved step by step.

Source: the official paper and answer key published by IIT Roorkee for GATE 2025 (official GATE site). Spotted a mistake? Email team@lemyte.com.

General Aptitude
10 · 15 marks
Electronics & Communication Engineering
55 · 85 marks
MCQ / MSQ / NAT
39 / 14 / 12
Marks to all
Q 8

Where the marks were

GATE 2025 EC topic-wise marks

Electronics & Communication Engineering questions only; General Aptitude adds 15 marks on top. The top three topics carried 36 of the 85 subject marks.

TopicQuestionsMarks
Networks, Signals and Systems913
Analog Circuits913
Control Systems610
Probability and Statistics59
Digital Circuits69
Electromagnetics48
Electronic Devices47
Communications56
Calculus34
Linear Algebra23
Complex Variables12
Differential Equations11

Free solved questions

5 solved questions from GATE 2025 EC

Question text and figures as in the official paper, the answer from the official key, and a worked solution. The other 60 solutions are in your report after you take the paper.

Q9 · General Aptitude · MCQ · 2 marks

The table lists the top 5 nations according to the number of gold medals won in a tournament; also included are the number of silver and the bronze medals won by them. Based only on the data provided in the table, which one of the following statements is INCORRECT?

NationGoldSilverBronze
USA404441
Canada392724
Japan201213
Australia171916
France162622
  • (A)
    France will occupy the third place if the list were made on the basis of the total number of medals won.
  • (B)
    The order of the top two nations will not change even if the list is made on the basis of the total number of medals won.
  • (C)
    USA and Canada together have less than 50% of the medals awarded to the nations in the above table.
  • (D)
    Canada has won twice as many total medals as Japan.

Answer (official key): C

Solution

Totals: USA 125, Canada 90, Japan 45, Australia 52, France 64; all together 376.

  • (A) France (64) is third: correct.
  • (B) USA and Canada stay first and second: correct.
  • (C) USA + Canada =215>188= 215 > 188 (50% of 376), so the statement is incorrect.
  • (D) 90=2×4590 = 2 \times 45: correct.

Q10 · General Aptitude · MCQ · 2 marks

An organization allows its employees to work independently on consultancy projects but charges an overhead on the consulting fee. The overhead is 20% of the consulting fee, if the fee is up to ₹ 5,00,000. For higher fees, the overhead is ₹ 1,00,000 plus 10% of the amount by which the fee exceeds ₹ 5,00,000. The government charges a Goods and Services Tax of 18% on the total amount (the consulting fee plus the overhead). An employee of the organization charges this entire amount, i.e., the consulting fee, overhead, and tax, to the client. If the client cannot pay more than ₹ 10,00,000, what is the maximum consulting fee that the employee can charge?

  • (A)
    ₹ 7,01,438
  • (B)
    ₹ 7,24,961
  • (C)
    ₹ 7,51,232
  • (D)
    ₹ 7,75,784

Answer (official key): B

Solution

For a fee F>5,00,000F > 5{,}00{,}000, the overhead is 1,00,000+0.1(F−5,00,000)=0.1F+50,0001{,}00{,}000 + 0.1(F - 5{,}00{,}000) = 0.1F + 50{,}000. The total billed is 1.18 (F+0.1F+50,000)=1.18 (1.1F+50,000)≤10,00,0001.18\,(F + 0.1F + 50{,}000) = 1.18\,(1.1F + 50{,}000) \le 10{,}00{,}000 1.1F≤8,47,457.6−50,000⇒F≤7,24,9611.1F \le 8{,}47{,}457.6 - 50{,}000 \Rightarrow F \le 7{,}24{,}961

Q39 · Networks, Signals and Systems · MCQ · 2 marks

In the circuit below, M1M_1 is an ideal AC voltmeter and M2M_2 is an ideal AC ammeter. The source voltage (in Volts) is vs(t)=100cos⁡(200t)v_s(t) = 100\cos(200t).

What should be the value of the variable capacitor CC such that the RMS readings on M1M_1 and M2M_2 are 25 V and 5 A, respectively?

Figure for GATE 2025 EC question 39 (Networks, Signals and Systems)

  • (A)
    25 µF
  • (B)
    4 µF
  • (C)
    0.25 µF
  • (D)
    Insufficient information to find CC

Answer (official key): A

Solution

M1M_1 reads the voltage across the series R–C–L branch and M2M_2 its current, so ∣Z∣=25/5=5 Ω=R|Z| = 25/5 = 5\ \Omega = R. The reactances must cancel (series resonance): ω2LC=1⇒C=1(200)2(1)=25 μF\omega^2 LC = 1 \Rightarrow C = \frac{1}{(200)^2(1)} = 25\ \mu\text{F} The LTI network between the source and the branch does not matter.

Q51 · Calculus · MSQ · 2 marks

Consider a non-negative function f(x)f(x) which is continuous and bounded over the interval [2, 8]. Let MM and mm denote, respectively, the maximum and the minimum values of f(x)f(x) over the interval.

Among the combinations of α\alpha and β\beta given below, choose the one(s) for which the inequality

β≤∫28f(x) dx≤α\beta \le \int_2^8 f(x)\,dx \le \alpha

is guaranteed to hold.

  • (A)
    β=5m, α=7M\beta = 5m,\ \alpha = 7M
  • (B)
    β=6m, α=5M\beta = 6m,\ \alpha = 5M
  • (C)
    β=7m, α=6M\beta = 7m,\ \alpha = 6M
  • (D)
    β=7m, α=5M\beta = 7m,\ \alpha = 5M

Answer (official key): A

Solution

Over an interval of length 6, 6m≤∫28f dx≤6M6m \le \int_2^8 f\,dx \le 6M. The inequality is guaranteed only if β≤6m\beta \le 6m and α≥6M\alpha \ge 6M (with m,M≥0m, M \ge 0).

Only (A) (5m≤6m5m \le 6m and 7M≥6M7M \ge 6M) satisfies both.

Q59 · Linear Algebra · Numerical · 2 marks

Consider the vectors

a=[11],b=[032].\boldsymbol{a} = \begin{bmatrix} 1 \\ 1 \end{bmatrix}, \qquad \boldsymbol{b} = \begin{bmatrix} 0 \\ 3\sqrt{2} \end{bmatrix}.

For real-valued scalar variable xx, the value of

min⁡x∥ax−b∥2\min_x \|\boldsymbol{a}x - \boldsymbol{b}\|_2

is ____________ (rounded off to two decimal places).

∥⋅∥2\|\cdot\|_2 denotes the Euclidean norm, i.e., for y=[y1y2]\boldsymbol{y} = \begin{bmatrix} y_1 \\ y_2 \end{bmatrix}, ∥y∥2=y12+y22\|\boldsymbol{y}\|_2 = \sqrt{y_1^2 + y_2^2}.

Answer (official key): 2.95 to 3.05

Solution

The least-squares solution is x∗=aTbaTa=322x^* = \dfrac{\boldsymbol{a}^T\boldsymbol{b}}{\boldsymbol{a}^T\boldsymbol{a}} = \dfrac{3\sqrt{2}}{2}.

The residual is b−ax∗=(−322,322)\boldsymbol{b} - \boldsymbol{a}x^* = \left(-\tfrac{3\sqrt{2}}{2}, \tfrac{3\sqrt{2}}{2}\right), with norm 9=3.00\sqrt{9} = 3.00.

The other 60 questions are solved in your report when you take GATE 2025 EC as a 3-hour test.

Take GATE 2025 EC as a test

Official answer key

GATE 2025 EC answer key

All 65 answers from the official key. Numerical answers are ranges; “or” means the key accepts either answer.

Download the official GATE 2025 EC answer key (PDF)
QTopicTypeMarksAnswer
1Verbal AptitudeMCQ1A
2Verbal AptitudeMCQ1D
3Quantitative AptitudeMCQ1B
4Analytical AptitudeMCQ1B
5Quantitative AptitudeMCQ1A
6Verbal AptitudeMCQ2B
7Analytical AptitudeMCQ2D
8Analytical AptitudeMCQ2Marks to all
9Analytical AptitudeMCQ2C
10Quantitative AptitudeMCQ2B
11Linear AlgebraMCQ1A
12CalculusMCQ1B
13Probability and StatisticsMCQ1A
14CommunicationsMCQ1A
15CommunicationsMCQ1A
16Control SystemsMCQ1D
17Networks, Signals and SystemsMCQ1D
18Networks, Signals and SystemsMCQ1A
19Networks, Signals and SystemsMCQ1A
20Networks, Signals and SystemsMCQ1A
21Analog CircuitsMCQ1A
22Analog CircuitsMCQ1C
23Digital CircuitsMCQ1A
24Digital CircuitsMCQ1B
25CalculusMSQ1A, B
26Control SystemsMSQ1C
27Networks, Signals and SystemsMSQ1C, D
28CommunicationsMSQ1A, D
29Analog CircuitsMSQ1A, C
30Analog CircuitsMSQ1B, D
31Electronic DevicesMSQ1A, D
32Differential EquationsNumerical10.25
33CommunicationsNumerical13
34Analog CircuitsNumerical150
35Digital CircuitsNumerical1250
36Control SystemsMCQ2D
37Control SystemsMCQ2A
38Networks, Signals and SystemsMCQ2A
39Networks, Signals and SystemsMCQ2A
40Networks, Signals and SystemsMCQ2A
41CommunicationsMCQ2D
42Probability and StatisticsMCQ2A
43Analog CircuitsMCQ2D
44Digital CircuitsMCQ2A
45Digital CircuitsMCQ2A
46Electronic DevicesMCQ2B
47Analog CircuitsMCQ2A
48Electronic DevicesMCQ2B
49ElectromagneticsMCQ2C
50ElectromagneticsMCQ2A
51CalculusMSQ2A
52Complex VariablesMSQ2A, B
53Control SystemsMSQ2B
54Probability and StatisticsMSQ2B, C
55Networks, Signals and SystemsMSQ2A, D
56Control SystemsMSQ2B
57Analog CircuitsMSQ2A, D
58Probability and StatisticsNumerical26.95 to 7.05
59Linear AlgebraNumerical22.95 to 3.05
60Probability and StatisticsNumerical20
61Analog CircuitsNumerical213.32 to 13.34
62Digital CircuitsNumerical2200
63Electronic DevicesNumerical20.23 to 0.24
64ElectromagneticsNumerical26.3 to 6.5
65ElectromagneticsNumerical20.62 to 0.63

Questions about GATE 2025 EC

How many questions are in the GATE 2025 EC paper?

65 questions for 100 marks: 10 General Aptitude questions worth 15 marks and 55 Electronics & Communication Engineering questions worth 85 marks. By type, there were 39 MCQs, 14 MSQs, 12 numerical answer (NAT) questions. The paper lasted 3 hours.

Is there negative marking in GATE 2025 EC?

Yes, for MCQs only. A wrong MCQ answer costs one-third of its marks (−⅓ for a 1-mark question, −⅔ for a 2-mark question). MSQ and numerical (NAT) questions have no negative marking, and an MSQ earns marks only when every correct option is chosen.

Which topics carried the most marks in GATE 2025 EC?

Outside General Aptitude, the biggest topics were Networks, Signals and Systems (13 marks), Analog Circuits (13 marks), Control Systems (10 marks). The full topic-wise split is in the table on this page.

Were any GATE 2025 EC questions awarded marks to all?

Yes. The official key awarded full marks to everyone for question 8.

Where does this GATE 2025 EC answer key come from?

From the official answer key published by IIT Roorkee, which organised GATE 2025. Range answers for numerical questions and questions with more than one accepted answer are kept exactly as the key gives them.

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